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Physics · Kinematics

A ball is thrown up at 20 m/s. Max height?

Step 1 — Concept

At max height, v = 0. Use v² = u² − 2gh.

Step 2 — Solve

h = u²/2g = 400/19.6 ≈ 20.4 m

💡Exam tip: g = 9.8 unless told otherwise.

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